Add a couple of answers
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README.md
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README.md
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:information_source: This repository contains questions on various DevOps and SRE related topics
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:information_source: This repository contains questions on various DevOps and SRE related topics
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:bar_chart: There are currently **738** questions
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:bar_chart: There are currently **740** questions
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:books: To learn more about DevOps check the resources in [DevOpsBit.com](https://devopsbit.com)
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:books: To learn more about DevOps check the resources in [DevOpsBit.com](https://devopsbit.com)
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@ -2937,6 +2937,23 @@ Last item: some_list[-1]
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```
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```
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sorted(some_list, reverse=True)[:3]
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sorted(some_list, reverse=True)[:3]
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```
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```
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Or
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```
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some_list.sort(reverse=True)
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some_list[:3]
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```
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</b></details>
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<details>
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<summary>Do you know what is the difference between list.sort() and sorted(list)?</summary><br><b>
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* sorted(list) will return a new list (original list doesn't change)
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* list.sort() will return None but the list is change in-place
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* sorted() works on any iterable (Dictionaries, Strings, ...)
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* list.sort() is faster than sorted(list) in case of Lists
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</b></details>
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</b></details>
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<details>
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<details>
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@ -2950,6 +2967,27 @@ nested_li = [['1', '2', '3'], ['4', '5', '6']]
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<details>
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<details>
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<summary>How to merge two sorted lists into one sorted list?</summary><br><b>
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<summary>How to merge two sorted lists into one sorted list?</summary><br><b>
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```
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sorted(li1 + li2)
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```
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Another way:
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```
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i, j = 0
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merged_li = []
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while i < len(li1) and j < len(li2):
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if li1[i] < li2[j]:
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merged_li.append(li1[i])
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i += 1
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else:
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merged_li.append(li2[j])
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j += 1
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merged_li = merged_li + merged_li[i:] + merged_li[j:]
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```
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</b></details>
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</b></details>
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<details>
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<details>
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@ -3008,6 +3046,12 @@ def my_func(li = []):
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If we call it 3 times, what would be the result each call?
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If we call it 3 times, what would be the result each call?
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</summary><br><b>
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</summary><br><b>
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```
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['hmm']
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['hmm', 'hmm']
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['hmm', 'hmm', 'hmm']
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```
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</b></details>
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</b></details>
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<details>
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<details>
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@ -3021,8 +3065,10 @@ for i in reversed(li):
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Method 2
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Method 2
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```
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```
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for i in li[::-1]:
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n = len(li) - 1
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while n > 0:
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...
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...
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n -= 1
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```
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```
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</b></details>
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</b></details>
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@ -3041,14 +3087,26 @@ list(zip(nums, letters))
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<details>
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<details>
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<summary>How to sort a dictionary by values?</summary><br><b>
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<summary>How to sort a dictionary by values?</summary><br><b>
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```
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{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
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```
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</b></details>
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</b></details>
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<details>
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<details>
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<summary>How to sort a dictionary by keys?</summary><br><b>
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<summary>How to sort a dictionary by keys?</summary><br><b>
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```
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dict(sorted(some_dictionary.items()))
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```
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</b></details>
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</b></details>
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<details>
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<details>
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<summary>How to merge two dictionaries?</summary><br><b>
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<summary>How to merge two dictionaries?</summary><br><b>
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```
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some_dict1.update(some_dict2)
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```
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</b></details>
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</b></details>
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##### Common Algorithms Implementation
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##### Common Algorithms Implementation
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@ -3458,6 +3516,44 @@ list(zip(range(5), range(50), range(-2)))
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```
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```
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</b></details>
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</b></details>
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#### Misc
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<details>
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<summary>Implement simple calculator for two numbers</summary><br><b>
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```
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def add(num1, num2):
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return num1 + num2
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def sub(num1, num2):
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return num1 - num2
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def mul(num1, num2):
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return num1*num2
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def div(num1, num2):
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return num1 / num2
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operators = {
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'+': add,
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'-': sub,
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'*': mul,
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'/': div
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}
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if __name__ == '__main__':
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operator = str(input("Operator: "))
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num1 = int(input("1st number: "))
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num2 = int(input("2nd number: "))
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print(operators[operator](num1, num2))
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```
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</b></details>
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<a name="python-advanced"></a>
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<a name="python-advanced"></a>
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#### :star: Advanced
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#### :star: Advanced
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